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18x^2-66x+56=0
a = 18; b = -66; c = +56;
Δ = b2-4ac
Δ = -662-4·18·56
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-18}{2*18}=\frac{48}{36} =1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+18}{2*18}=\frac{84}{36} =2+1/3 $
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